i don't know what is wrong with my idea. I tried many times but still wrong answer. can anyone tell me what is wrong?
source : http://www.spoj.com/problems/GSS2/
№ | Пользователь | Рейтинг |
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1 | tourist | 4009 |
2 | jiangly | 3821 |
3 | Benq | 3736 |
4 | Radewoosh | 3631 |
5 | jqdai0815 | 3620 |
6 | orzdevinwang | 3529 |
7 | ecnerwala | 3446 |
8 | Um_nik | 3396 |
9 | ksun48 | 3388 |
10 | gamegame | 3386 |
Страны | Города | Организации | Всё → |
№ | Пользователь | Вклад |
---|---|---|
1 | cry | 164 |
1 | maomao90 | 164 |
3 | Um_nik | 163 |
4 | atcoder_official | 161 |
5 | -is-this-fft- | 158 |
6 | awoo | 157 |
7 | adamant | 156 |
8 | TheScrasse | 154 |
8 | nor | 154 |
10 | Dominater069 | 153 |
i don't know what is wrong with my idea. I tried many times but still wrong answer. can anyone tell me what is wrong?
source : http://www.spoj.com/problems/GSS2/
Название |
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I can't see how you handled the idea of removing duplicates. I solved it using a offline approach. Quora has a nice tutorial on it.
It is harder than GSS3, GSS4 and GSS5. Maybe you want to try them first if you are going to solve them all.
i also use offline. i sort the queries wrt right position. if any value appear previously I set 0 at the previous position of the segment tree, and insert the value at the current position. then i use GSS1.
Explain this:
tn.ms = max({0LL, l.ms, r.ms, l.rs+r.ls});