Hello, I was trying to solve the problem http://uva.onlinejudge.org/external/109/10913.html but i think that it has a mistake in the problem description, in according to the rules: - You can move left, right and down - You can step at most K times, and you can not step one cell more than once
For the first case:
n = 4, k = 1
1 2 3 -5
-10 6 0 -1
-10 -10 -10 2
0 0 0 1
I think that you can go for the next path: (1,1) -> (1,2) -> (1,3) -> (2,3) -> (2,2) -> (4,2) -> (4,3) -> (4,4) right right down left step_down right right
Getting as a maximum sum path : 1 + 2 + 3 + 0 + 6 + 0 + 0 + 1 = 13 But the sample output is 11.
Please, tell me if i am wrong, i do not sure that i understood the problem because to get 11 as output you can not go left :s
Thanks in advance.








You can't get from (2, 2) to (4, 2).
So, what is the correct path??? And what does "at most K steps" mean? Does it mean "you can have at most k negative numbers in your path"?
Thanks
You go 1, 2, 6, 0, -1, 2, 1. The sum is 11. How did you get (2,2) -> (4,2)?
I was so wrong, I did not understand the problem, great mistake, before reading this problem, I was reading another one where you could jump, (go over some cells) and I confused some things with this problem. I am sorry.