You are given an array of size n find number of distinct digits in the numbers in a given range ? I know how to do it with segment tree , please help me to do it with Binary indexed tree .
thanks in advance :)
# | User | Rating |
---|---|---|
1 | tourist | 3856 |
2 | jiangly | 3747 |
3 | orzdevinwang | 3706 |
4 | jqdai0815 | 3682 |
5 | ksun48 | 3591 |
6 | gamegame | 3477 |
7 | Benq | 3468 |
8 | Radewoosh | 3462 |
9 | ecnerwala | 3451 |
10 | heuristica | 3431 |
# | User | Contrib. |
---|---|---|
1 | cry | 167 |
2 | -is-this-fft- | 162 |
3 | Dominater069 | 160 |
4 | Um_nik | 158 |
5 | atcoder_official | 156 |
6 | Qingyu | 155 |
7 | djm03178 | 152 |
7 | adamant | 152 |
9 | luogu_official | 150 |
10 | awoo | 147 |
You are given an array of size n find number of distinct digits in the numbers in a given range ? I know how to do it with segment tree , please help me to do it with Binary indexed tree .
thanks in advance :)
Name |
---|
You can use one BIT per digit so you can easily found the frequency of any given digit in a range. You can solve every query in O(D * log(N)) where D = 10.
You know how to do it with segment tree then you must be familiar with the logic. Then I guess problem is in the implementation part.
Here is my solution.
thanks Abhay :)
By the way if you have multiple queries which can be processed offline, this can also be done using square root decomposition (also referred to as Mo's algorithm).