How can this problem be solved with persistent segment tree??Although there are other methods to solve this but i am interested in persistent segment tree!!
# | User | Rating |
---|---|---|
1 | tourist | 3856 |
2 | jiangly | 3747 |
3 | orzdevinwang | 3706 |
4 | jqdai0815 | 3682 |
5 | ksun48 | 3591 |
6 | gamegame | 3477 |
7 | Benq | 3468 |
8 | Radewoosh | 3462 |
9 | ecnerwala | 3451 |
10 | heuristica | 3431 |
# | User | Contrib. |
---|---|---|
1 | cry | 167 |
2 | -is-this-fft- | 162 |
3 | Dominater069 | 160 |
4 | Um_nik | 158 |
5 | atcoder_official | 157 |
6 | Qingyu | 155 |
7 | djm03178 | 151 |
7 | adamant | 151 |
9 | luogu_official | 150 |
10 | awoo | 147 |
How can this problem be solved with persistent segment tree??Although there are other methods to solve this but i am interested in persistent segment tree!!
Name |
---|
Since Ai <= 10**5, you could maintain a segment tree for each i such that it contains 1 in its jth position if arr[j] >= i.
You could form segment tree for ith index from i+1 index easily. Overall there would be total n updates. Hence O(nlogn) For querying start at root of Lth index and apply binary search to get position of kth value. O(qlogn)
AC code here