How to count the number of rectanglular submatrix with all 1s in a binary square matrix of size N in O(N^2)?
i have a solution for o(N^3)
| # | User | Rating |
|---|---|---|
| 1 | Benq | 3676 |
| 2 | jiangly | 3670 |
| 3 | Kevin114514 | 3657 |
| 4 | maroonrk | 3355 |
| 5 | Um_nik | 3353 |
| 6 | squareOf105 | 3346 |
| 7 | tourist | 3343 |
| 8 | strapple | 3324 |
| 9 | heuristica | 3322 |
| 10 | jiangbowen | 3291 |
| # | User | Contrib. |
|---|---|---|
| 1 | Qingyu | 158 |
| 2 | nik_exists | 150 |
| 2 | maspy | 150 |
| 4 | AmShZ | 143 |
| 5 | Um_nik | 141 |
| 6 | Errichto | 139 |
| 7 | adamant | 137 |
| 8 | BledDest | 134 |
| 9 | maroonrk | 133 |
| 10 | qwexd | 130 |
How to count the number of rectanglular submatrix with all 1s in a binary square matrix of size N in O(N^2)?
i have a solution for o(N^3)
| Name |
|---|



Nice question! Like you, i am only solving the O(N^3) algorithm with two pointer technique, and i guess O(N^2 Log N) with divide and conquer maybe..
I solved it finally.
i used histograms + range in which current is minimum + radix sort to calculate the range.
Thanks anyways
.
Test your idea with this problem from COCI. My O(N^2 Log N) idea get TLE.