Hi everyone, so I found this problem today, and it seems like a really obvious bipartite matching, but I've been getting TLE in it. Is there some faster way to solve it?
| # | User | Rating |
|---|---|---|
| 1 | Benq | 3676 |
| 2 | jiangly | 3670 |
| 3 | Kevin114514 | 3657 |
| 4 | maroonrk | 3355 |
| 5 | Um_nik | 3353 |
| 6 | squareOf105 | 3346 |
| 7 | tourist | 3343 |
| 8 | strapple | 3324 |
| 9 | heuristica | 3322 |
| 10 | jiangbowen | 3291 |
| # | User | Contrib. |
|---|---|---|
| 1 | Qingyu | 158 |
| 2 | nik_exists | 150 |
| 2 | maspy | 150 |
| 4 | AmShZ | 143 |
| 5 | Um_nik | 141 |
| 6 | Errichto | 139 |
| 7 | adamant | 137 |
| 8 | BledDest | 134 |
| 9 | maroonrk | 133 |
| 10 | qwexd | 130 |
| Name |
|---|



O(VE) bipartite matching algorithm obviously gets TLE on dense graph with such limits. I think solution which runs in O(sqrt(v) * E) will pass. For example you can use "Hopcroft–Karp algorithm".
Sorry, forgot to say I used Hopcroft-Karp.
Strange... Show your code, maybe i can help. Solution with O(N ^ 2.376) exists, but i think Hopcroft-Karp must pass.
Here it is: http://pastebin.com/3RH9u4SN
Your algorithm works in O(VE) time and it isn't Hopcroft-Karp. Just try this testcase: 500 500
2 2 2 2 2 ... (500 times)
2 2 2 2 2 ... (500 times)
Copy this a few times and then add "0 0". Your algorithm will work more then 5 seconds (and will get TLE).
Thanks, I found the mistake, I was using the || operator instead of |= when updating the variable change. With this change it still isn't Hopcroft karp because i'm not taking shortest paths, but that only makes it a bit slower.
Dinnic works here, my solution accepted in 4.86 seconds.