Hello I am solving this problem . I am confused on how to fill up the graph so that I can implement shortest path using bfs.
| # | User | Rating |
|---|---|---|
| 1 | Benq | 3676 |
| 2 | jiangly | 3670 |
| 3 | Kevin114514 | 3657 |
| 4 | maroonrk | 3355 |
| 5 | Um_nik | 3353 |
| 6 | squareOf105 | 3346 |
| 7 | tourist | 3343 |
| 8 | strapple | 3324 |
| 9 | heuristica | 3322 |
| 10 | jiangbowen | 3291 |
| # | User | Contrib. |
|---|---|---|
| 1 | Qingyu | 158 |
| 2 | nik_exists | 150 |
| 2 | maspy | 150 |
| 4 | AmShZ | 143 |
| 5 | Um_nik | 141 |
| 6 | Errichto | 139 |
| 7 | adamant | 137 |
| 8 | BledDest | 133 |
| 8 | maroonrk | 133 |
| 10 | qwexd | 130 |
Hello I am solving this problem . I am confused on how to fill up the graph so that I can implement shortest path using bfs.
| Name |
|---|



For every number from 1 to MAXM * 2 , you can push i * 2 and i — 1 in its adjacency list and after doing that , start a bfs from n and print distance[m]. Code -> 10110821
bfs