jaswanthi's blog

By jaswanthi, 10 years ago, In English

I came up a solution for the following problem.

But, I want to do it in true recursive way. Can you help with coming up with Pair<int,int> or Object.

Problem:

Given a binary tree, find the maximum path sum. It can contain -ve values

The path may start and end at any node in the tree. For example: Given the below binary tree,


1 / \ 2 3

Return 6.

Given the below binary tree,

       -2
         \
         -1

Return -1.

Solution with Global variable way:

int max = Integer.MIN_VALUE
public int calculateSum(TreeNode root) {
	if (root == null)
		return 0;

	int left = calculateSum(root.left, max);
	int right = calculateSum(root.right, max);

	int current = Math.max(root.val, Math.max(root.val + left, root.val + right));

	max = Math.max(max, Math.max(current, left + root.val + right));

	return current;
}
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10 years ago, # |
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You can return pair<max sum, head of list representing the best way>. So you can choose pair with greater sum, and add current node to list in O(1).

Wow, I thought the task is to find the best descending path in binary tree.

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10 years ago, # |
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Am I the only one who can't see no global variables here? Could you describe a problem a bit carefully — what do you want?