| № | Пользователь | Рейтинг |
|---|---|---|
| 1 | Benq | 3676 |
| 2 | Kevin114514 | 3659 |
| 3 | jiangly | 3640 |
| 4 | turmax | 3450 |
| 5 | tourist | 3382 |
| 6 | strapple | 3360 |
| 7 | Um_nik | 3354 |
| 8 | squareOf105 | 3348 |
| 9 | maroonrk | 3312 |
| 10 | idontwannadothis…e | 3191 |
| Страны | Города | Организации | Всё → |
| № | Пользователь | Вклад |
|---|---|---|
| 1 | Qingyu | 155 |
| 2 | nik_exists | 151 |
| 3 | maspy | 149 |
| 4 | AmShZ | 145 |
| 5 | Um_nik | 143 |
| 6 | Errichto | 139 |
| 7 | BledDest | 136 |
| 8 | adamant | 134 |
| 9 | maroonrk | 132 |
| 10 | cry | 130 |
| Название |
|---|



In fact there are many generalizations of Cayley theorem (though I didn't know that particular one).
One was given as a problem on Putnam competition one year ago: http://www.artofproblemsolving.com/Forum/viewtopic.php?p=3315688&sid=56608f6bc111f1ce8bcfb33ff1220ce3#p3315688
Here is another one I know. Assume that we want to compute number of forests on n vertices with k trees such that vertices with indiced 1, ..., n belong to other trees. Then number of them is equal to knn - k - 1.
Despite the fact that there are many of them I always got problems even with proving basic version :p.