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By bharadwaj75, 10 years ago, In English

printf("%d",scanf("%d",&a)) gives always 1 .Can any one tell what is the actual logic behind that?

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10 years ago, # |
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printf returns the number of items of the argument list successfully filled normally, in this case the return value is 1.

For more, view the section "Return Value" on this page.

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10 years ago, # |
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It is not necessary 1, obviously the answer is the output of scanf(...), and if it works properly it is all the variables it could, read or -1 in eof

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10 years ago, # |
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scanf returns the number of read items.

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10 years ago, # |
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1 means true

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    10 years ago, # ^ |
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    No, it doesn't! 1 is the number of read elements.

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    10 years ago, # ^ |
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    If you write printf("%d",scanf("%d%d",&a,&b)) it will give 2

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