How can we solve spoj problem INCSEQ using segment tree?
Here is the link to the problem
# | User | Rating |
---|---|---|
1 | tourist | 3856 |
2 | jiangly | 3747 |
3 | orzdevinwang | 3706 |
4 | jqdai0815 | 3682 |
5 | ksun48 | 3591 |
6 | gamegame | 3477 |
7 | Benq | 3468 |
8 | Radewoosh | 3462 |
9 | ecnerwala | 3451 |
10 | heuristica | 3431 |
# | User | Contrib. |
---|---|---|
1 | cry | 167 |
2 | -is-this-fft- | 162 |
3 | Dominater069 | 160 |
4 | Um_nik | 158 |
5 | atcoder_official | 156 |
6 | Qingyu | 155 |
7 | djm03178 | 152 |
7 | adamant | 152 |
9 | luogu_official | 150 |
10 | awoo | 147 |
How can we solve spoj problem INCSEQ using segment tree?
Here is the link to the problem
Name |
---|
I think, that you can solve this task in such way :
You will use K segment trees.
1. Sort all elements of given array in non-decreasing order.
About sort : if elements are equal — the minimal element will be element which has the rightmost position.
2. You should update every segment tree in such way :
3. Le'ts add the value of sum in the current segment tree in position myElementPosition.
My AC code here
If I want to find distinct increasing subsequence as in this question http://www.spoj.com/problems/INCDSEQ/
what modification I need to make in the above code?
Another ways to solve the problem:
Can you please explain how BIT is working for this problem? Also , why we need to increment a[i] during scanning the input
Increment is because BIT is 1-based structure. Bit-based solution is simply in k turns calculate on each turn number of sequences of length i ending in pos.