Oh hello there. This is chromate00, just casually on the announcement of Codeforces Round 1009 (Div. 3). And now, you see a drawing.
$$$\square$$$ — $$$\triangle$$$ — $$$\triangle$$$ — ◯ — $$$\triangle$$$ — $$$\square$$$ — $$$\triangle$$$
And then, you think. You see a square, a triangle, and a circle. Also, a Korean problemsetter. You immediately imagine the certain survival game that popped up in your memory. And you may be right. Or you might be wrong. Whatever, what I can ensure you is that you will be absolutely stunned to see the problems. Or astonished. You might not believe what you see. This round might change everything.
Anyways, the preface was a bit too long. Starting from Mar/11/2025 17:35 (Moscow time), you will be given $$$\mathbf{7}$$$ problems to be solved in $$$\mathbf{2.5}$$$ hours. There is at least one interactive problem, so I strongly urge you to read the guide if you are unfamiliar with the format.
The round will be hosted by rules of educational rounds (extended ICPC). Thus, all solutions will be judged on preliminary tests during the round, and after the round, there will be a 12-hour phase of open hacks. After the open hack phase, all accepted solutions will be rejudged on successful hacks. Also, note that there is no score distribution but the usual penalty of 10 minutes for each wrong submission, following the rules of educational rounds.
Remind yourself that only the trusted participants of the third division will be included in the official standings table. As it is written by link, this is a compulsory measure for combating unsporting behavior. To qualify as a trusted participant of the third division, you must:
- take part in at least five rated rounds (and solve at least one problem in each of them)
- not have a rating of 1900 or higher at any moment in time.
Regardless of whether you are a trusted participant of the third division or not, if your rating is less than 1600, then the round will be rated for you (unless you register unrated).
Also, note the (relatively recent) rule restricting the use of AI. If you are caught while breaking this rule, you will be terminated.
This round is made possible by the help of the following people:
- cry and Vladosiya for coordinating the round (and translating the statements),
- Proof_by_QED for reviewing the tasks (and not so particularly testing them),
- Our army of (not so) pink soldiers: Intellegent, amoeba4, mathtsai, Error_Yuan, temporary1, Edeeva, yeetholmes619, beaten_by_ai, larush, pop, (VIP) Dominater069, (VIP) Friedrich, (VIP-) macaquedev, antontrygubO_o, Mercuria, DivinePunishment, 0pt1mus23, pianapolataa, reirugan, efishel, (VIP) awesomeguy856, rewhile, __baozii__, yoru_sacri, -firefly-, sbreger60, monadtransformer, Rahuldeb5,
- The VVVIP, MikeMirzayanov, for great platforms Codeforces and Polygon.
I hope that you will also be in the spectacular moment.
UPD: Editorial has been posted.
UPD2: Congratulations to the top participants definitely except for the ones who cheated their way out!
All participants:
Trusted (rated) participants:
- sharvil_cpp
Xing_Kong_C......has been terminated- jxu
- 1zaid1
- eysikingE
- PlasticMemories
- Lappland_the_Decadenza
As a tester, cherry without her is cry
TheScrasse is my favorite cherry.
As a tester, I can confirm that this round is somehow ralated to squid games!
As an author, I can confirm that this round is in no way affiliated to squid game
So,is this round ralated to PlayStation?
As an author, I can confirm that this round is in no way affiliated to PlayStation
Do we get the 45.6 billion won, If we complete all 7 problems?
As a tester, this round was shocking.
as a tester, IVE PLAYED THESE GAMES BEFORE!!!
As a tester, I can confirm there are two squares, four triangles and a circle in the announcement.
As a tester, I can confirm there are more than a circle in the announcement.
As a tester, I can confirm I'm poi's crazy fan!
as a tester, i can confirm chromate00 cooked the greatest div3 ever made
Is he obsessed with geometry ? :))
As a tester, this round is enjoyable!
As a first time tester, this was truly one of the rounds of all time.
As a tester, I was indeed stunned to see the problems.
As a tester, cry offers poor people for testing and forces them to play children's games.
As a (not so) pink soldier, your life may be on the line this round... so I hope you get AC!
As a tester, if I catch any of you using AI in an illegal manner, I will personally order chromate00 to yeet you into the Ohio river.
very sigma
Sigma sigma on the wall, who's the skibidiest of them all?
It's you, yes, it's you, top sigma bricked_.
First time as an unrated participant
STPC 2025 Spring when? xD
soon(TM)
Score Distribution:
□ — math
△ — greedy/dp
◯ — speedforces
Put your predictions here
v
□ — speedforces/math △ — dp/greedy/binarysearch ◯ — interactive
Occam's razor would claim that the simplest, most elegant explanation is usually the one closest to the truth
□ — geometry
△ — geometry
◯ — geometry
how does it feel to predict the contest
I have a feeling that there will be more than one interactive problem.
Last time a Div. 3 have interactive is Div. 3 Round 988.
It was at problem E and very balanced.
Let's hope we're having a blast too.
Hoping to climb back to EXPERT !!
;gimme 1530
I will give my best to be back to CYAN in today's round, inshaAllah!
May be not this time. But, hopefully next time...
If you are caught while breaking this rule, you will be terminated.
I hope to become a specialist after this round.
chromate00 orz !!!
Why is there (VIP) before the name of some testers?
Going to give my very first contest today, Hopefully Codeforces Round 1009 (Div. 3) Ends Up Good For Me!
This Blog Missing You for particirating
Why give 7 geometry problems?
“Codeforces Geometry Round 1009 (Div. 3)”
GeometryForces!
If you know someone who needs a geometry sheet, send them this contest.
It turns out that I had been warned in advance
I love the sudden change of topic.
Thanks for the contest!
I mean, you needn't to eat too much geometric figure...
This kinda contest is Errichto's wet dream~ He would surpassed tourist, no doubt!
Those who participated Div3 today
even though I am not geometry enjoyer, best div 3 round I have participated in
Div.3 is not meant for you. For most pupils and specialists, this is a trash round
I haven't said its meant for me, just said that it was my favourite div 3 round lol. Also why is it a "trash" round for most pupils and specialists?
I agree this contest is the worst ever div3 I joined, no variety as usual
Guys, if u love geometry and wanna similar contest solve topic based or even make it official rounds but alert us to not join similar contests that has no variety
not sure what u mean, there are lots of variety
there is a variety, but all ideas are around geometry.
consider the following contest A- Give n and m (num nodes and num edges) check if ..... B- Given n and m and m edges, do something that require DP C- Given a tree, do something that require binary search D- Given n and m and m edges, do some DP Bitmasks E- Given n and m and m edges, do some greedy thing and so on
so if someone is not comfortable with graph at all it will be a nightmare for him which is unfair
funny thing about B is i did not read the problem i just saw the test cases and figure it out it is just
sum-n+1Yes ^_^, first three problems were ez (3rd was great), don't require much imagination
here's the alert:
"□ — △ — △ — ◯ — △ — □ — △"
here
Yes, I hope I understood early :(
I liked the round ^_^
.
same bro, like usually any problem solved by 3k+ people till like div 2, I usually know at least how to proceed, in this one I gave full 45 mins to the question(I knew I wont be able to do E and G) but still couldn't figure out a single thing
Welp. I really did not like this round. I feel like the problems (considering this is div 3) are just getting creative for no reason. For instance, E is just... I don't know how one does that.
do you want tasks to be uncreative?
Don't get me wrong, obviously codeforces is not meant to be something like CSES. But it feels like there's barely any consistency anymore, so those that are not already at a high level that can easily adapt have a hard time progressing any further. For instance, do you think that geometry is really a good test for division 3? I think absolutely not.
funny thing is the most "geometry" problem is A (and that is weakly geometry).
All the tasks have geometry settings, but nothing to do with actual geometry. (for example, half the tasks are just about definition of triangle, which is a simple mathematical concept)
I knew someone was gonna point this out. But I mean, take E. What is that supposed to test? I spent 2 hours thinking about that and still only thought of a probabilistic solution that still failed multiple times. Unless there is some real insight that I missed, a problem like that is pointless in div 3. Things like implementation, greedy, sorting, basic data structures, case analysis, etc. should be the focus of div 3.
i agree that E is not a good problem in a round, but at the same time, I think its a ok educational problem. The insight to take away is that randomized algorithms are something to consider as well. For example, take last div1A/div2C, some people solved it through randomization since they were too skill issued to solve normally. (and its applicable to a lot of places)
i was not really defending the round, just pointing out a fun fact about how the round is geometry but not at all geometry at the same time.
E was guesswork
I get what you mean, when starting its easier to focus on a limited amount of techniques and algorithms, but in all fairness its the same for everyone and i think it would be benificial for most to get to know a lot more topics then just the few kind of problems codeforces has been limited to in lower divisions. The memes of pupils knowing segment trees are there for a reason.
For example on E randomized Las Vegas algorthims, are really not too hard to understand and actually really cool!
Specifically with E, what is one supposed to do when exceeding the query limit (my submissions will show TLE if you check because I put that as a tripwire to tell me I had too many queries) since this is a random problem. I did a random solution but consistently exceeded the queries....
your solution would work if the point given by the adaptive interactor would be random. Instead of replacing always the first point you should replace a random one.
Thanks. I will remember this day when I jump off a building (look at my rating graph for reference) smh.
The problem statements clearly explains how to handle query limits and wrong answers. Essentially, your program should immediately quit (i.e. call
std::exit(0)for C++,sys.exit()for Python) whenever-1is read (for $$$n$$$ or as a response to a query).The statements of many past interactive problems were fairly vague on when the interactor gives
-1, but this problem actually does a good job on this.I think you misunderstood what I meant. I was pointing out the problem with having a randomized problem in a round, not the fact that it is "difficult" to determine when the queries are exceeded.
As long as your program handles
-1properly, you will receive the WA verdict when your program exceeds the query limit. You don't have to count your queries yourself and do infinite loop or whatever -- just implement what is stated in the statements and you will receive the correct verdict.next contest will have twosum
Why on mirrors that are not behind cloudflare (like mirror.codeforces.com or m1.codeforces.com) images are still behind cloudflare and are not displayed? Very inconvenient for such a round where several problems have images.
[deleted]
what geometry knowledge is required?
Being comfortable with x axis and y axis and drawings on them and imagine how things go so you can solve (visualizations) for example I do this on graphs on a software and I used to do this with graph for this contest I was searching for any similar thing like geogebra and I was suffering consider this suffering for many problems ex: for problem D I was trying this software and make a circle to see patterns tgen I found that I have drawn many trying to fix this so delete my main circle and ahhh... (I know for u, you may not draw or even read the problem to get ACC, but for me now I do this)
nondeg idea for traingle if someone saw it many times he can solve quickly, but if someone saw it for the first time today and it was in two consecutive problems it is not something good, like I remember when I saw it for the first even its translation to my language was not ez to understand until I knew it just mean to be able to make a triangle
yes, even first problem Ok its sol is all dirs should be equal, but why not for example letting every side be equal to the other three like (d2 + l2) == (d2 + r2) == (u2 + l2) ....
I did this for the first time and got penality so just guessed all should be equal, but to be sure I should draw and be comfortable with geometry
Problems A, B, C, D, and E involved geometric figures to some extent. Since I couldn't come up with a good idea for problem E, I assumed that it required a strong understanding of geometry. Now that I know problem E isn't a geometry problem, I see that my assumption was incorrect.
P.S. It turned out that in problem E, I simply forgot to input N
Bro i couldnt even solve C my bitwise problems are cooked ;-;
was E just a luck checking task or there is some formal proof ?
Someone tell me how you did D pls
There is atmost O(m) possible value of x for a "good" point.
Let f(x) denote the largest integer y such that the point (x, f(x)) is a good point.
Then, the answer is the sum of 2 * f(x) + 1 over all x values.
can you explain how are duplicates counted once?
Note that we are iterating over every x value only once so there is no overcounting.
Both C and D makes me sweat in keyboard and note + pen.
Have no time left for actually solve E.
Please explain c
First you have number a, make b = reserve a (i.e if a = 1011, -> b = 0100)
it's easy to see a ^ b = c = 1111 (all 1)
Now it's time for trickery happens, My solution is try to increase b while decrease c to make a good triangle triplet.
To do so find the right most bit 1 of a (called j), then set b[j] = 1 so that c[j] = 0.
Remember to check the a b c again to fit the condition (b < a), if not print -1.
you can just bruteforce it, try all possibility from 1 to 10000 is enough
i guess , that can be hacked
how do you solve D?
The problemsetter did hint you on small m. Try solve on range of all circles with height = [0, max(r)]
is the approach as follows then:
This would give TLE i think.
You can try to hack my solution, overall complex is accept-able.
1 more crucial hint: due to small m the almost brute forcing on sum all range is O((m+n)* log(m+n))
I could only solve A :(
i couldn't even solve a single problem
You should be joking, A was very easy. I got stuck in C with TLE—cons of using python I assume.
Too much geometry tho, I didn't even try anything past C. Since this is also my first-ever contest.
From their submissions i'm guessing they didn't get time to solve and when they came back they could only solve problem A in last 5 minutes of contest.
E is the most "guess till you AC" problem i have ever seen, thanks for the round.
fr
The compiler on CodeForces is so stupid, it gave me compilation error because i used "goto" keyword on problem C.
Nah, your code is bad and the compiler is correct, according to the C++ standard. See cppreference.
Finally, the following solution worked (still using goto multiple times). https://codeforces.me/problemset/submission/2074/310172545
All I had to do was to split every statement (which contains the initialization of variables that get skipped over by goto) into two statements (one statement contains the declaration and one statement contains assignment: using '=' operator).
Not sure why microsoft visual studio doesn't catch such compilation error even though I have all warnings turned on.
Anyway, this compile-error is very stupid in my opinion.
It's not very hard to deal with those compile errors. Basically you need to move the variable definitions up before any goto statements and labels.
You can change this:
to this:
The C++ standard clearly says a goto jumping over variable definitions with initializers is ill-formed, so the compilers must issue a warning or an error when they see such gotos ("ill-formed" means the compilers must issue a diagnostic).
And there's a good reason why such gotos are prohibited. Essentially they screw up constructors and destructors. The constructor and the destructor of an object must be called exactly once each, but gotos screw up object lifetimes pretty badly. Think about the following example:
How to solve $$$G$$$ ?
and btw, was the intended solution for problem $$$E$$$ to use randomization ?
because I used a randomization solution and it got AC
yes this is heavily hinted upon (no hacks, only 35 hardcoded test cases)
$$$G$$$ can be solved with dynamic programming. Let $$$dp_{i,j}$$$ (with $$$i \lt j$$$) be the maximum score IF you only use points from $$$i$$$ to $$$j$$$. For the transition, notice that there are two cases.
The first case is when you create a triangle with points $$$i \lt k \lt j$$$. You gained $$$a_i \cdot a_k \cdot a_j$$$ points, and you are left with unused points from $$$i + 1$$$ to $$$k - 1$$$ and from $$$k + 1$$$ to $$$j - 1$$$ respectively. Since we cannot draw triangles that cross each other, these two segments are isolated. Thus, the maximum points you can gain in this case is $$$a_i \cdot a_k \cdot a_j + dp_{i + 1, k - 1} + dp_{k + 1, j - 1}$$$.
The second case is you split it into two segments $$$[i, k]$$$ and $$$[k + 1, j]$$$, where $$$i \lt k \lt j$$$, which is just $$$dp_{i, k} + dp_{k + 1, j}$$$.
The final answer is $$$dp_{1, n}$$$. Since $$$i \lt k \lt j$$$, this results in $$$O(n^2)$$$ states and $$$O(n)$$$ transition, which is $$$O(n^3)$$$ total. With the constraint on $$$k$$$, try to see why these two cases cover all possible configurations.
on E : random bullshit go
Triangleforces :(((
Today's contest was just me vs. geometry... and geometry won!
For E, I had the following algorithm:
while(fr!=0) do :
k = fr
ask(i,j,k)
Set fr as frontmans response
5.answer(i,j,k)
Can somebody explain the flaw behind this because I was getting wrong answer
it won't work because the frontman's response is adaptive
imagine this scenario:
according to your algorithm, the time complexity will be $$$O(n)$$$ which will take upto $$$1500$$$ queries
Now I understand what u mean be the first two paragraphs and the drawing, I hope I understood before the contest to not join
Was E more about fooling the system (test cases), or is there a way to definitely get an answer (with proof of how 75 queries will always suffice)?
Kindly refer to the editorial (it is similar to why random pivot quicksort works)
Hey, can you proof why my solution $$$\leq$$$ 75 queries or your test is just too weak.
310098939
sadly I could not kill ALL deterministic heuristics (refer to the editorial's comments for why)
So why did you disable hack for this problem?
if there is no bound on the number of the test cases, then one could not bound the probability to get AC either.
Is there a deterministic solution for E?
I think a few heuristics passed, while theoretically no. It ws impossible to kill all of them :(
what is the logic behind E?
Kindly refer to the editorial
One of the contests of all time!
Seriously, are contests being revised before being published for us to solve and if so how this contest was allowed isn't variety one of the criteria.....
For a website with a small number of users, i wonder why this websites loads very,very slowly during contest times even with good good internet connection. I spent also most 6 mins just to load the first problem and immediately after contest ends, the speed goes back to normal. And to think the problem setter decided to make the most stupid problems to compound my misery, making me regret why i even gave this contest in the first place.
I didnt encounter such problem
What even is this statement in problem D :(
Please find the number of integer points inside or on the border of at least one circle.
got it now. Damn my english :D
Oh man, this contest was harder than the usual Div. 3, especially C. I really liked D btw, I was stuck for some time until I realized I could sweep from the left.
same, I thought on binary search for D but failed miserably. Then I brute force sweep from left and AC for about 20-30 minutes
hey could you please explain me the logic for D, for overlapping x for two circles? I tried to subtract the common points for two circles as i proceeded from left to right but then i realised i might be subtracting the same points twice for 3 circles which overlap and didnt know what to do further.
Simply avoid subtract, only plus with 2 pointers.
If you are talking about the inclusion-exclusion principle, the limit of $$$n$$$ is way too large for that to work.
Instead, imagine a vertical line sweeping from the far left to the far right on the x-axis. You can quickly calculate the number of integer points on that line that are contained in some circles. Since the sum of radii is bounded by $$$m$$$, the answer can be found in $$$O(m)$$$.
what's wrong in my recursive dp in Problem G 310149712
wtf was even the logic for e , just random bullshit guessing ??
Naive random guessing failed for me. Instead, initialize with a random guess, if it works then you're done. Otherwise take the new point inside the triangle plus randomly pick 2 of your previous 3 points to carry forward to the next iteration.
How to solve G
As a participant, round is awesome
Oh, my dearest chrom chromate00 ater. I used to think we were of opposition.
But that was until this very day! I realized that I was only under a circumstance called “skill issue.”
Alas, I was eventually enamored by your brilliance, and unskilled my issue until I fell in love with the chrome that is ater... Zero zero.
In problem D, shouldn't sum of n overall test cases also not exceed 2e5? I was confused with this during the contest and wasted a lot of time thinking about it.
it is bounded by $$$n \le m$$$ if you see the constraints
Thanks to the authors, for the fact that I may have become a specialist.
Great contest! Thanks to the writer(s)
i envy people that are calling these problems geometry because they clearly never suffered trying to solve an ICPC geometry problem...
Agreed !! None was a Geometry heavy problem !! It was just a themed contest.. All that was used in Geometry was Middle School Maths !!
How did you practice? Your rating graph is really something
yours too
Now I am feeling really dumb
chill, it was meant to be a fun comment. keep coding. good luck.
Season 2 when?
I don't really think the round was too focused on geometry. Despite that all problems were geometry-themed, this round didn't really involve any problem of which the key technique/knowledge required was geometry. A, D, and E might be a bit geometric, but the geometry part isn't even the hardest part of the problem and should be trivial for anyone who tries these problems (not saying that the problems are easy, but the actual difficult part isn't geometry.)
To be honest, I find much more rounds being too much focused on bitwise operations by having like 3 problems around the similar category, and it feels like more than half of the rounds nowadays are heavily focused on math that is not geometry. It felt pretty good to see some geometries (at least mildly) once in a while. Also, this round actually tried to introduce variety in problems, each requiring a different skillset in different categories.
Believe it or not, my least favorite problem in this round was C because I'm so tired with all the XOR problems and I was hoping not to encounter them for a while, and I fatally struggled so much on it again (it took me more time to solve than D, E, and F.) But overall I really liked this round.
For me, most hard part is geometry(especially on D) :( I'm going to middle school and i don't even found how to count the numbers of points in a circle. In this case how can i found the algorithm for D? I can't understand editorial too.
btw C was easiest problem for me except for A :D
The only geometry knowledge you need for D is that whether a point is inside a circle is determined by the distance between the point and the center of the circle. The distance between $$$(x,y)$$$ and $$$(x',y')$$$ is $$$\sqrt{(x-x')^2+(y-y')^2}$$$, so you just need to check if this is less than or equal to $$$r_i$$$ (better to square both sides to avoid precision errors by using integers only). This information is already given in the statement as well.
The rest of the solution is that for each circle you check every $$$x$$$s from $$$x_i-r_i$$$ to $$$x_i+r_i$$$ and find the largest $$$y$$$ that satisfies the inequation, which can be directly done by reordering the inequation or by binary search, and this process isn't much related to geometry.
I guess the reason you felt this problem hard is not because you lacked of geometry knowledge, but because you failed to come up with the idea of bruteforcing every $$$x$$$, which makes the part of using the formula trivial with one of the coordinates fixed.
i kinda understood what you mean but what does (x′,y′) coordinates mean?
It's just an arbitrary name given for the second point's coordinate in the general formula of the distance between two points. In this problem, you may assume that $$$x'=x_i$$$ and $$$y'=0$$$ for each circle, which leads to the requirement written in the statement.
Why is F so hard ?
Hard because of thinking ? No, hard because of understanding :)
Yeah literally it took so much time for me to understand the problem and deduce it
There should be variety in problems. It's not fair to create entire round on the same concept. It gets too much boring and this might cause fatigue for people who don't really enjoy geometry even though they can solve the problems and this can ruin their performance.
There are $$$14$$$ distinct tags over $$$7$$$ problems now, clearly you are not seeing the apparent diversity that people see...
I am just saying that everything is related to points and geometrical figures which becomes too much monotonous and boring especially for someone who is not much interested in geometry like me.I agree there are greedy, probability and bit manipulation kind of topics involved but I never saw any contest yet on cf which is entirely based on a single concept.Correct me if I am wrong on my last statement.
However, look at actual recent contests. Notice how you can enumerate what the tasks might look like, even before looking into the problemset. "You are given an array, do blah blah blah on it, then solve blah blah blah queries.", "You are given function blah blah blah, calculate the sum of function blah blah blah on all blah blah blah", etc. And almost every such moment, you can think of a tag in your mind, and almost every five tasks you will get it correctly. Don't you think this is weird? Do you think this is the real meaning of variety?
Honestly, I do not get your point in variety. I could only read "I hate geometry" in your intentions.
Yeah I understand what you mean. Agree, thats actually how it happens. And yes my opinion might be based on my bias against geometry :(
Anyways thanks for your clarification.
There is something called Themed Contest !! The problems involved many other algorithms and tags; it was just that they all were embedded in a geometrical story. And even; if Geometry was used anywhere; it was hardly above the level of mid school maths !! And what bad is solving a Geometry Dash contest?? If you're good at Geometry, you will do well. And if you're not; such contests would motivate you towards learning Geometry !!
Why isn't there any system testing or ratings update?
Please be patient as system testing shall begin after we sort out the quite concerning issue of literally a hundred inputs added to the tests for C
no way magnus has 1500 elo xD
Pretests were so weak. LMAO.
sadly it may have f*cked the queue if it were any stronger
,
Your submissions for A, B and C are identical or almost identical. However thv_1311's submissions came 1 to 3 minutes before yours ...
Hello, so I got this message that my submission for D no. problem is similar to some random dudes submission who I don't even know. As far as I am concerned, I abode by the rules of codeforces and reached the solution my self while using AI for only direct translation to Bengali and Autocompletion tool Copilot and Codeium. Now all my submissions show skipped. What do I do and how do I proof that there were no cheating or plagiarism. Help please
Okay so as per the instruction, I'll provide my thought process for my solution for the problem:
I started things off by imagining the circles on the plane and quickly realized that since the center of each circle sits on the x-axis, tackling the problem one horizontal line (or “slice”) at a time makes it a lot easier. For every fixed y-value, I figured out the range of x-values that fit within each circle using the circle equation. This naturally led me to create intervals of valid x-coordinates.
Then, since multiple circles could create overlapping intervals on the same y-line, I combined those intervals to ensure I didn’t count any point more than once. Since, each circle contributes intervals for each y in the range [-ri, ri]. I realized that different circles might contribute intervals at the same y-coordinate. So, I thought of using a dictionary (or defaultdict) to collect all intervals for every y-value across all circles.
I worked on refining this method on my own through several iterations and tests.
This was my overall thought process... Do I need to provide technical walkthrough too?
shocking news: cheater fails to not cheat while appealing for cheating
Can you please elaborate?
...It is dead obvious that you asked GPT to elaborate about ITS approach. which is not YOUR approach.
Oh, as for that, yes, I did use GPT, but only to translate my answer into proper English since I’m not very good at it. I gave it my broken response and asked it to structure my thought process clearly. I did the same for this reply, as well as for my daily interactions in English.
for which case GPT should have said "your" instead of "my"...
Your argument does not even make sense now, I kindly ask you to stop trying more or else I will ask the administrator to disable your account immediately instead of giving you a light punishment.
How can one get rank 1 and 2 by cheating? Any other reasons for termination? chromate00
rank 2 used GPT and there were obvious signs of teaming
we suspected rank 1 for alting but probably it was false positive
for this contest, I don't have access to my own computer, & I used OneCompiler site to run my codes, also I didn't know anything about their settings and privacy for showing codes to others , and I think that's why someone submit similar code to mine , about an hour after me
that was funny contest with nice problems, thank you :)