69eloChess's blog

By 69eloChess, history, 2 years ago, In English

You are given an integer N and a prime P. Count the number, modulo P, of undirected connected graphs G of N vertices numbered 1 to N that satisfy the following conditions:

There are no self-loops in G. Note that multiple edges are allowed.

For all edges (u,v) in G, if we delete (u,v) from G, G remains connected. In other words, G is edge-biconnected.

For all edges (u,v) in G, if we delete (u,v) from G, G is no longer edge-biconnected. Two graphs are considered different if and only if there exists a pair of distinct vertices (u,v) such that the numbers of edges connecting u and v in the two graphs are different.

N<=50, P<=1e9

Input : Two integers N and P

Output: Print the answer.

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2 years ago, hide # |
 
Vote: I like it +23 Vote: I do not like it

This ain't 1400, it's the hardest problem of the last AGC.

E — Biconnected Graph