Hello, I tried to solve this problem with Suffix Array : 452E - Три строки . I have seen some solution but unable to understand the idea. Can anyone give me the idea to solve the problem using Suffix Array?
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1 | tourist | 3993 |
2 | jiangly | 3743 |
3 | orzdevinwang | 3707 |
4 | Radewoosh | 3627 |
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1 | cry | 167 |
2 | Um_nik | 163 |
3 | maomao90 | 162 |
3 | atcoder_official | 162 |
5 | adamant | 159 |
6 | -is-this-fft- | 158 |
7 | awoo | 155 |
8 | TheScrasse | 154 |
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Hello, I tried to solve this problem with Suffix Array : 452E - Три строки . I have seen some solution but unable to understand the idea. Can anyone give me the idea to solve the problem using Suffix Array?
Название |
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This is my rough idea:
abc$bc%cbc
) and compute its SA and LCP:C
. For each of the three stringsS
and each (necessary) lengthL
, maintain the number of suffixT
ofS
that is already seen such thatC[1...L]==T[1...L]
.This is my actual code: 7273217. The numbers I maintained is put in
stack<T> st;
. I (unnecessarily) used binary index tree for range-modification.