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By heinous_coder, history, 4 months ago, In English

So this is not a post accussing someone but more of a post for understanding the problem.

I was giving Codeforces 944 Div 4. I had done 5 problems but the next day it shows that the solution to my 5th problem has been hacked. I took the hack test case and when I ran it on my local machine, the answer matched the expected output but when I ran it on codeforces, it shows some deviation from the expected output.

The code ~~~~~

Code

The Test Case ~~~~~ 1 45 16 33 6 26 28 32 34 35 36 37 38 39 40 41 42 43 44 45 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 26 9 15 2 14 44 20 28 29 11 23 40 15 45 17 9 7 15 29 28 19 5 36 18 3 40 9 22 32 26 3 1 13 ~~~~~

for the 4th query the answer should be 15 but my solution when ran on codeforces servers produces the answer 14.

I know that instead of calcuating speed I could have just used dist and time in the final expression but still I want to know why my answer comes out correct on my local but is wrong on codeforces.

Please help.

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4 months ago, # |
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4 months ago, # |
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When I solve this question I applied the approach same as yours like a separate variable for speed then computing the final answer, but it gave me WA whereas putting everything into a single expression comes out to be the accepted answer.

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    4 months ago, # ^ |
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    Same here. But the code is running fine on my local machine. Don't know what's the issue here. This question wasted a lot of my time as I was multiplying by speed to find time and now just because of this variable my solution has been hacked.

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4 months ago, # |
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4 months ago, # |
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Generally, you shouldn't use floating-point data types when not needed. Because there will be precision errors and you always want to avoid that whenever possible

With that being said, I don't exactly know why it happens on that particular test case though. Also, are you sure that your ind + 1 isn't accessing out-of-bounds?

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4 months ago, # |
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If you do this

double timeTaken = b[ind] + (d - a[ind]) / speed;
cout << fixed << setprecision(50) << (long double)timeTaken << " ";

You will see that this value is actually 14.99999999999999999913263826201159645279403775930405

I can't say exactly why we don't see that with just double, but the problem is still here — the precision of the floating point types

Probably it would better to use round here (or a solution without using double at all)

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2 months ago, # |
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