Why downvotes are in the announcement? don't be a kid!

HOPE to solve A....This is my first atcoder contest ;}

Why can't I pass problem D!!! The contest will be finished in 18 min!

Bruh, C was so annoying. Solved D in like ~10 minutes, but wasted so much time thinking for C :<

what is mistake in my code for D

https://atcoder.jp/contests/abc320/submissions/45643786

Well, I spend 30 min to understand what C was saying!

Task G it seems flow without any optimization passed.

can anybody please tell me a counter test case for C problem according to my code. or where my logic is wrong?

ll n; cin >> n;

    string s1, s2, s3; cin >> s1 >> s2 >> s3;

    

    map < char, vector < ll >  > mp1, mp2, mp3;

    for(ll i = 0; i < sz(s1); i++)
    {
        mp1[s1[i]].push_back(i);

    }

    for(ll i = 0; i < sz(s2); i++)
    {
       mp2[s2[i]].push_back(i);

    }
    for(ll i = 0; i < sz(s3); i++)
    {
        mp3[s3[i]].push_back(i);
    }


    ll mn = LLONG_MAX;
    for(char i = '0'; i <= '9'; i++)
    {
        for(auto x : mp1[i])
        {
            for(auto y : mp2[i])
            {
                for(auto z : mp3[i])
                {
                    if(x != y and y != z and z != x)
                    {
                        x %= n, y %= n, z %= n;
                        ll mx = max({x, y , z});
                        mn = min(mx, mn);
                    }
                }
            }
        }
    }
    if(mn != LLONG_MAX)
    {
        cout << mn; return;
    }

    ll got = 0;

    for(char i = '0'; i <= '9'; i++)
    {
        if(sz(mp1[i]) > 0 and sz(mp2[i]) > 0 and sz(mp3[i]) > 0)
        {
            got = 1;
            break;
        }
    }

    if(got == 0)
    {
        cout << "-1";
    }




    if(s1 == s2 and s2 == s3 and s3 == s1)
    {
        cout << n; return;
    }

Me wasting 40 minutes on C not realizing there were only 3 slot machines. :(

For $$$C$$$, You can just make 3 consecutive copies of each string ($$$S_i =S_i + S_i + S_i$$$).

Try every digit[0:9] and if you found 3 different indices have the same digit, minimize the maximum index with the answer . Code : 45651190

can somebody tell me why i am stuck in problem D

https://atcoder.jp/contests/abc320/submissions/45651936

in the editorial of F: in the fourth case we need to iterate right? so how the complexity will stay O(n^3) ? https://atcoder.jp/contests/abc320/editorial/7169

Sub AtCoder it locked my account without any email or notice.

fu!

The data of question C is suggested to be strengthened

this is the hack input

8
12221222
13313331
44414414

answer:

4

Output the wrong answer '6' but accepted code. https://atcoder.jp/contests/abc320/submissions/45625948

This hack can block some greedy algorithms, including me.

For problem G: (1) (2)

The (1) code shows about 7 times slower than (2) for test 5, and it gets TLE. (2) is AC, and the difference between (1) and (2) is the way of adding the element to the b array: for (1), i use (line 135 to 141)

        for(int i=1; i<=n; i++){
            int cur = 0;
            while(b[i].size() < n){
                b[i].push_back(b[i][cur] + m);
                cur++;
            }
        }

for (2) (line 134 to 137):

            int ts = tmp.size();
            for(int k=0; k<n; k++){
                b[i].push_back(tmp[k % ts] + m * (k / ts));
            }

Why is (1) so slow? Very thanks!