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find the maximum subset vertices of DAG
By start_over, history, 16 months ago, In English

Given a DAG (V, E), find the maximum subset V' of V so that every vertex in V' can't reach other vertices in V'. |V| <= 3000, |E| <= 20000

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16 months ago, # |
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Auto comment: topic has been updated by start_over (previous revision, new revision, compare).

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16 months ago, # |
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The problem wants the largest antichain in the poset defined by the transitive closure of the DAG (so we assume that the graph is the transitive closure of itself — this can be done in $$$O(VE)$$$). You can show that it is the size of the min-cut in the graph defined as follows: the vertex set consists of a source $$$s$$$ and a sink $$$t$$$, every vertex $$$v$$$ in the DAG corresponds to two vertices $$$v_1, v_2$$$, there are edges $$$(s, v_1)$$$ and $$$(v_2, t)$$$, and for any $$$(u, v)$$$ in the DAG, there is an edge $$$(u_1, v_2)$$$. All edges have capacity $$$1$$$. Since this is a unit network, finding the max flow using Dinic will be $$$O(E \sqrt{V})$$$, and recovering the min cut can be done in linear time. So the overall complexity is $$$O(VE + V^{2.5})$$$.

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    16 months ago, # ^ |
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    I'm not sure if this is the correct solution or not. For the DAG with no edge, the answer is |V|, but the min-cut for graph created by your solution is 0.

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      16 months ago, # ^ |
      ← Rev. 5   Vote: I like it +12 Vote: I do not like it

      My bad, I had intended to write the complement of the min cut in some sense instead of the min cut. The vertices that form an antichain are the vertices $$$v$$$ such that $$$v_1$$$ and $$$v_2$$$ are in different partitions of the cut. Hopefully this clears the confusion.

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