Can anyone help me out with this problem, I looked up on many places but couldn't find any satisfactory solution
| № | Пользователь | Рейтинг |
|---|---|---|
| 1 | Benq | 3676 |
| 2 | Kevin114514 | 3659 |
| 3 | jiangly | 3640 |
| 4 | turmax | 3450 |
| 5 | tourist | 3382 |
| 6 | strapple | 3360 |
| 7 | Um_nik | 3354 |
| 8 | squareOf105 | 3348 |
| 9 | maroonrk | 3312 |
| 10 | idontwannadothis…e | 3191 |
| Страны | Города | Организации | Всё → |
| № | Пользователь | Вклад |
|---|---|---|
| 1 | Qingyu | 158 |
| 2 | nik_exists | 151 |
| 3 | maspy | 149 |
| 4 | AmShZ | 144 |
| 5 | Um_nik | 143 |
| 6 | Errichto | 139 |
| 7 | adamant | 136 |
| 8 | BledDest | 133 |
| 9 | maroonrk | 132 |
| 10 | cry | 130 |
Can anyone help me out with this problem, I looked up on many places but couldn't find any satisfactory solution
| Название |
|---|



you can just simply search for cycle in undirected graph and keep a parent array if you find cycle just backtrack using parent array
tried that but it fails in the case my dfs starting point is in the cycle as it would have no parent
Once you reach an already visited node X which isn't the parent keep pushing parent-nodes into vector until you reach X Then terminate the dfs and print the ans