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Codeforces (c) Copyright 2010-2024 Mike Mirzayanov
The only programming contests Web 2.0 platform
Server time: Sep/23/2024 12:22:39 (l3).
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Supported by
dpA[i] =dpA[i-1] + (s[i]=='A') * numofQ[1,i-1]
dpQ[i]= dpQ[i-1] + (s[i]=='Q') * dpA[i-1]
final answer is dpQ[n]
Your approach is too good
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