I wanted to go into details — but it would have been a full 30 minutes. Any suggestion/query is welcome.
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I wanted to go into details — but it would have been a full 30 minutes. Any suggestion/query is welcome.
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I don't think your solution can pass the system test. I think it will be TLE. In the worst case, updating the nodes' information can be O(n); So it's O(q*n)? Did I misunderstand? :D
updating will take O(log(n)) per query. Something like:
So, we are building the data structure for LCA incrementally after each query.
For more info check out "Another easy solution in <O(N logN, O(logN)>" section on TC