Given 2 strings ,determine if they are anagrams of each other.
example :
input:
listen silent
output:
True
| # | User | Rating |
|---|---|---|
| 1 | Benq | 3676 |
| 2 | Kevin114514 | 3659 |
| 3 | jiangly | 3640 |
| 4 | turmax | 3450 |
| 5 | tourist | 3408 |
| 6 | strapple | 3360 |
| 7 | Um_nik | 3354 |
| 8 | squareOf105 | 3348 |
| 9 | maroonrk | 3312 |
| 10 | idontwannadothis…e | 3191 |
| # | User | Contrib. |
|---|---|---|
| 1 | Qingyu | 155 |
| 2 | nik_exists | 151 |
| 3 | maspy | 149 |
| 4 | AmShZ | 145 |
| 5 | Um_nik | 143 |
| 6 | Errichto | 139 |
| 7 | BledDest | 136 |
| 8 | adamant | 135 |
| 9 | maroonrk | 132 |
| 10 | cry | 130 |
Given 2 strings ,determine if they are anagrams of each other.
example :
input:
listen silent
output:
True
| Name |
|---|



Sort the strings and check if they are equal.
I suggest you use hashing. A good hashing function in this case is adding the characters, since anagrams will result in the same sum!
No way this goes wrong!
I think this code helps with your problem, although it's a bit long, it is easily understandable and a brute-force solution.
Hope you find it easy...