Hi :)
Given n can you find a uniformly random correct bracket sequence with 2 * n characters?
(uniformly random means all possible answer for the problem have same probability for the outcome of the algorithm)
Codeforces Round 1133 (Div. 1, Div. 2) is coming soon! Register here.
→ Pay attention
→ Top rated
| # | User | Rating |
|---|---|---|
| 1 | Benq | 3676 |
| 2 | Kevin114514 | 3659 |
| 3 | jiangly | 3640 |
| 4 | turmax | 3450 |
| 5 | tourist | 3382 |
| 6 | strapple | 3360 |
| 7 | Um_nik | 3354 |
| 8 | squareOf105 | 3348 |
| 9 | maroonrk | 3312 |
| 10 | idontwannadothis…e | 3191 |
→ Top contributors
| # | User | Contrib. |
|---|---|---|
| 1 | Qingyu | 155 |
| 2 | nik_exists | 151 |
| 3 | maspy | 149 |
| 4 | AmShZ | 145 |
| 5 | Um_nik | 143 |
| 6 | Errichto | 139 |
| 7 | BledDest | 136 |
| 8 | adamant | 134 |
| 9 | maroonrk | 132 |
| 10 | cry | 130 |
→ Find user
→ Recent actions
A random problem!
Revision en1, by SaSa, 2016-06-28 19:39:20
History
Revisions
| Rev. | Lang. | By | When | Δ | Comment | |
|---|---|---|---|---|---|---|
| en4 |
|
SaSa | 2016-07-06 17:47:16 | 1 | Tiny change: 'characters?<br>\n(un' -> 'characters ?<br>\n(un' | |
| en3 |
|
SaSa | 2016-06-29 15:57:17 | 1 | Tiny change: 'characters ?<br>\n(un' -> 'characters?<br>\n(un' | |
| en2 |
|
SaSa | 2016-06-29 15:56:38 | 1 | Tiny change: 'characters?<br>\n(un' -> 'characters ?<br>\n(un' | |
| en1 |
|
SaSa | 2016-06-28 19:39:20 | 238 | Initial revision (published) |
Codeforces (c) Copyright 2010-2026 Mike Mirzayanov
The only programming contests Web 2.0 platform
Server time: Nov/06/2026 21:56:22 (g2).
Desktop version, switch to mobile version.
Supported by
