Recently, K1o0n made an impulsive purchase of $$$n$$$ packs of tea and is now wondering when he will manage to try all the blends. He is picky about tea, so he immediately assigned each pack a strength — an integer $$$a_i$$$.
The packs are arranged on the shelf in the order they were bought, and K1o0n is too lazy to sort them out: when brewing tea, he pours the first $$$j$$$ packs in order into the teapot, and then adds one more spoon from the pack with number $$$i$$$. We denote the resulting blend by $$$(i, j)$$$, and define its strength as the product of the strengths of everything that went into it:
$$$$$$F(i, j) = a_i \cdot \prod_{k=1}^{j} a_k = a_i \cdot \left(a_1 \cdot a_2 \cdot \ldots \cdot a_j\right)$$$$$$
K1o0n pours the finished teapot into identical cups: he can pour it into $$$d$$$ cups if and only if $$$d$$$ — is a natural divisor of the number $$$F(i, j)$$$, and each cup gets the same amount. He calls a blend capricious if the number of suitable $$$d$$$ is odd.
Count how many capricious blends K1o0n can brew, that is, how many pairs $$$(i, j)$$$ with $$$1 \le i \le n$$$ and $$$1 \le j \le n$$$ give an odd number of natural divisors of the number $$$F(i, j)$$$.
The first line contains an integer $$$t$$$ ($$$1 \le t \le 10^4$$$) — the number of testcases.
The first line of each testcase contains an integer $$$n$$$ ($$$1 \le n \le 2 \cdot 10^5$$$) — the number of tea packs.
The second line of each testcase contains $$$n$$$ integers $$$a_1, a_2, \ldots, a_n$$$ ($$$1 \le a_i \le 10^6$$$) — the strengths of the teas.
It is guaranteed that the sum of $$$n$$$ over all testcases does not exceed $$$2 \cdot 10^5$$$.
For each testcase, output one integer — the number of capricious blends.
Note that the answer may not fit into a 32-bit type. Use a 64-bit type (long long in C++, long in Java).
442 3 6 44974153 980051 988027 1812 3 5 45 1 7 63 2113
44111