B. Minimise Oneness
time limit per test
1.5 seconds
memory limit per test
256 megabytes
input
standard input
output
standard output

For an arbitrary binary string $$$t$$$$$$^{\text{∗}}$$$, let $$$f(t)$$$ be the number of non-empty subsequences$$$^{\text{†}}$$$ of $$$t$$$ that contain only $$$\mathtt{0}$$$, and let $$$g(t)$$$ be the number of non-empty subsequences of $$$t$$$ that contain at least one $$$\mathtt{1}$$$.

Note that for $$$f(t)$$$ and for $$$g(t)$$$, each subsequence is counted as many times as it appears in $$$t$$$. E.g., $$$f(\mathtt{000}) = 7, g(\mathtt{100}) = 4$$$.

We define the oneness of the binary string $$$t$$$ to be $$$|f(t)-g(t)|$$$, where for an arbitrary integer $$$z$$$, $$$|z|$$$ represents the absolute value of $$$z$$$.

You are given a positive integer $$$n$$$. Find a binary string $$$s$$$ of length $$$n$$$ such that its oneness is as small as possible. If there are multiple strings, you can print any of them.

$$$^{\text{∗}}$$$A binary string is a string that only consists of characters $$$\texttt{0}$$$ and $$$\texttt{1}$$$.

$$$^{\text{†}}$$$A sequence $$$a$$$ is a subsequence of a sequence $$$b$$$ if $$$a$$$ can be obtained from $$$b$$$ by the deletion of several (possibly, zero or all) elements. For example, subsequences of $$$\mathtt{1011101}$$$ are $$$\mathtt{0}$$$, $$$\mathtt{1}$$$, $$$\mathtt{11111}$$$, $$$\mathtt{0111}$$$, but not $$$\mathtt{000}$$$ nor $$$\mathtt{11100}$$$.

Input

The first line contains an integer $$$t$$$ ($$$1 \leq t \leq 10^4$$$) — the number of test cases.

The only line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 2\cdot10^5$$$) — the length of $$$s$$$.

It is guaranteed that the sum of $$$n$$$ over all test cases does not exceed $$$2\cdot10^5$$$.

Output

For each test case, output $$$s$$$ on a new line. If multiple answers exist, output any.

Example
Input
3
1
2
3
Output
0
01
010
Note

In the first test case, for the example output, $$$f(t)=1$$$ because there is one subsequence that contains only $$$\mathtt{0}$$$ ($$$\mathtt{0}$$$), and $$$g(t)=0$$$ because there are no subsequences that contain at least one $$$1$$$. The oneness is $$$|1-0|=1$$$. The output $$$\mathtt{1}$$$ is correct as well because its oneness is $$$|0-1|=1$$$.

For the example output of the second test case, $$$f(t)=1$$$ because there is one non-empty subsequence that contains only $$$\mathtt{0}$$$, and $$$g(t)=2$$$ because there are two non-empty subsequences that contain at least one $$$\mathtt{1}$$$ ($$$\mathtt{01}$$$ and $$$\mathtt{1}$$$). The oneness is thus $$$|1-2|=1$$$. It can be shown that $$$1$$$ is the minimum possible value of its oneness over all possible binary strings of size $$$2$$$.