| # | User | Rating |
|---|---|---|
| 1 | jiangly | 3810 |
| 2 | Benq | 3676 |
| 3 | Kevin114514 | 3655 |
| 4 | maroonrk | 3463 |
| 5 | strapple | 3447 |
| 6 | Um_nik | 3387 |
| 7 | heuristica | 3322 |
| 8 | turmax | 3317 |
| 9 | tourist | 3307 |
| 10 | jiangbowen | 3291 |
| # | User | Contrib. |
|---|---|---|
| 1 | Qingyu | 156 |
| 2 | nik_exists | 150 |
| 2 | maspy | 150 |
| 4 | Um_nik | 141 |
| 5 | Errichto | 139 |
| 6 | adamant | 137 |
| 7 | AmShZ | 135 |
| 8 | BledDest | 132 |
| 9 | maroonrk | 131 |
| 10 | qwexd | 129 |
|
0
don't know how to fix it( added code |
|
0
oh, sry, fixed now |
|
+4
Your solution didn't TL on some large tests, may be problem in infinite loop (also we opened tests) There solution with formula for searching min x in $$$O(1)$$$: 157928657 Code |
|
On
100mil →
If anyone could help me as to why the way I use BFS always ends up getting TLE., 5 years ago
+6
The problem in this line:
Your there is your AC solution with this fix 138716320 And write "\n" instead endl, because endl flushing output, what takes time (sorry for my bad english) |
|
+1
I think it because if $$$a$$$ $$$xor$$$ $$$b$$$ == $$$c$$$ it means that $$$a$$$ $$$xor$$$ $$$c$$$ = $$$b$$$, so if you found indexes $$$i$$$ and $$$j$$$ and $$$a_i$$$ $$$xor$$$ $$$b_j$$$ $$$=$$$ (number in second array), you can choose this number and get $$$a_i$$$ $$$xor$$$ (this number) = $$$b_j$$$. If this number in first array, you can choose (this number) $$$xor$$$ $$$b_j$$$ = $$$a_i$$$. So if you found pair you can also find another pair. |
|
0
i have same problem( |
|
0
|
| Name |
|---|


