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0
I am not able to find what's wrong in this solution for E, can somebody help :) 177207734 |
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+17
Did anyone else also thought that the lid can be moved more than once in Problem C :") |
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0
Wrong Ans on test case 46, what? :( 176324763 |
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0
For C1: Firstly count the number of all possible pairs i.e. n+nC2. Now we subtract the pair which is not possible. In the equation max(0,i-a[i]-q)*(n-i+1), max(0,i-a[i]-q) represents the no of options of choosing the left l and (n-i+1) represents the no of right choices. Here to avoid re-counting q is used which represents all the left before q are already chosen. |
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+4
Take an example a = {4,2,4}. Let the array b={b1,b2,b3,b4}. since gcd(b1,b2)=4, b2 is a multiple of 4 and since gcd(b3,b4)=4, b3 is a multiple of 4. Therefore the greatest common divisor of b2 and b3 will be a multiple of gcd(4,4)=4 (i.e. a[i] must be a multiple of gcd(a[i-1],a[i+1])). We cannot construct the array when it is not a multiple. (sorry for any language mistakes :)) |
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+4
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0
Thanks! |
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0
Can anyone please check why my code is failing on pretest 3 173225741 |
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0
Did Problem D just 15 seconds after the contest :( |
