let array A = {1,3,1,1,1,4,0,0,2,3,1,}
We have to do following 2 operations on it
1.)Decrease all elements from L to R by 1
2.)Given i find right most element j such that for each k. i <= k <= j. A[k] > 0
how can i do this in log(N)
?
# | User | Rating |
---|---|---|
1 | tourist | 4009 |
2 | jiangly | 3823 |
3 | Benq | 3738 |
4 | Radewoosh | 3633 |
5 | jqdai0815 | 3620 |
6 | orzdevinwang | 3529 |
7 | ecnerwala | 3446 |
8 | Um_nik | 3396 |
9 | ksun48 | 3390 |
10 | gamegame | 3386 |
# | User | Contrib. |
---|---|---|
1 | cry | 167 |
2 | Um_nik | 163 |
3 | maomao90 | 162 |
3 | atcoder_official | 162 |
5 | adamant | 159 |
6 | -is-this-fft- | 158 |
7 | awoo | 156 |
8 | TheScrasse | 154 |
9 | Dominater069 | 153 |
9 | nor | 153 |
let array A = {1,3,1,1,1,4,0,0,2,3,1,}
We have to do following 2 operations on it
1.)Decrease all elements from L to R by 1
2.)Given i find right most element j such that for each k. i <= k <= j. A[k] > 0
how can i do this in log(N)
?
Name |
---|
yeah use binary search
Stop learning useless algorithms, go and solve some problems, learn how to use binary search — by (You know this :p)
i didn't asked for suggestion. go and solve Watermelon problem :p